Microsoft Word - Dosumu_061210_proof.doc

20 ± 0.8 D 35 ± 0.5 40 ± 0.5 45 ± 0.1 3 ± 0.2 5 ± 0.5 T. Solium P 15 ± 0.4 D 40 ± 0.3 37 ± 0.3 42 ± 0.3 5 ± 0.5 40 ± 0.5 P. Pasthuma P 40 ± 0.2 D > 60 8 ± 0.9 60 ± 0.5 20 ± 0.3 60 ± 0.5 a) mean time in minutes [...] mean ± SD b) 12.5 mg/ml c) 25 µg/ml Microorganism EtOAc extractb) MeOH extractb) Isolatec) Ampicilinc) S. typhi 12 ± 0.3 12 ± 0.3 9 ± 0.2 19 ± 0.2 E. coli 12 ± 0.4 12 ± 0.3 9 ± 0.2 15 ± 0.5 P. aeruginosa [...] of crude methanol extract Diameter of zone of inhibition (mm)a) a) Values are mean ± SD b) 12.5 mg/ml c) 0.5 mg/ml of 1% w/v Both ethyl acetate and methanol ex- tracts (10 mg/ml) were very active in invok- …

Microsoft Word - Schupp_consumer_risk_100309proof.doc

foam About 5 g foam (10 cm x 10 cm x 1 cm) was cut from the surface and from the mid- dle of the cushion (size of cushion: 40 cm x 40 cm x 10 cm, density 30 g/L) and weighed (accuracy ± 0.5 mg). The foam [...] Nagel). Eluent: acetonitrile/water (50/50) with 2.5 g tri- ethylamine and 0.77 g ammonium-acetate per litre, pH = 6.3 (adjusted with acetic acid). Flow: 1.5 mL / min. Detector: UV- VIS 254 nm fixed. RESULTS [...] filter extracts which had been in contact with both sides of the foam for 5 days at 22 °C. Therefore, the migration of MDI over 5 days is less than 1 µg/22.68 cm² = 44 ng/cm² or, continuous migration over …

reelep-ud-040321a.dvi

T being defined as (L′ ? enh) T = [ ξ 0 0 0 0 0 ξ 0 ] . (5.5) 124 1. International Colloquium on High-Speed Forming In summary, the relation 5.1 represents a non-linear equation to determine the internal [...] 33 B3 ξ J0 t + 4 3 BT 3 ηA ? 33 B3 η J0 t + 4 9 BT 3 ξηA ? 33 B3 ξη J0 t (5.9) Using Equation 5.3, the second line of Equation 5.6 reduces to (Khg uuPS + K hg uu 33 − Kuw K−1 ww Kwu)U e := Kstab U e. Due [...] order tensors is constructed analogously, whereas the fourth order tensors are accordingly reduced to 5x5 matrices. We now work with the interpolation (indicated by the index h) Hh PS = (B0 + j0 Lhg Mhg)U …

Microsoft Word - Jatwa_Kar_proof.doc

as both drugs increased 5’DI activity and se- rum T3 concentration (Fig. 2). No signifi- cant alteration in serum T4 level was no- ticed. Fig. 1 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 Control CCl4 CCl4 + Lornit [...] 12 ±1.01 ±2.13 ±2.21 ±2.01 ±2.63 GSH 3.50 2.07*** 4.23+++ 5.07+++ 4.09* 4.72* ±0.21 ±0.10 ±0.31 ±0.42 ±0.42 ±0.41 Renal SOD 4.72 3.36** 5.50+++ 5.21+++ 7.10** 8.12*** ±0.32 ±0.22 ±0.35 ±0.36 ±0.6 ±0.7 CAT [...] triiodothyronine (T3), thyrox- ine (T4), glucose and insulin and in hepatic type-1 iodothyronine 5’monodeiodinase (5’DI) activity were considered as major parameters. Simultaneously activities of serum aspartate …

do.tu-dortmund.de/bitstreams/982d0f11-5c70-474d-b97f-3ce796e4c42a/download","type":"image/jpeg"},{"href":"https://eldorado.tu-dortmund.de/bitstreams/5c9a44d8-27d5-4633-a82d-c3fc8f78a3ff/download","typ [...] de/bitstreams/d68e412b-7003-4722-9ada-cd02b5ff42c0/download","type":"text/html"},{"href":"https://eldorado.tu-dortmund.de/bitstreams/72a7d29a-2b1c-466c-b892-a5e5dd36a070/download","type":"text/html"},{" [...] 7/download","type":"image/jpeg"},{"href":"https://eldorado.tu-dortmund.de/bitstreams/4ce43a5c-c2ff-454b-baf5-7a5306a8ae4c/download","type":"image/jpeg"},{"href":"https://eldorado.tu-dortmund.de/bitstr …

ruppe Kontrollgruppe 86,18 80,75 3,960 5,964 2 Experimentalgruppe Kontrollgruppe 90,09 79,75 2,877 5,077 3 Experimentalgruppe Kontrollgruppe 93,68 80,80 2,950 5,764 4 Experimentalgruppe Kontrollgruppe [...] Lautstärke 5 Lautstärke 6 21 21 21 21 21 21 0,123 0,182 0,185 0,288 0,255 0,174 0,563 0,834 0,849 1,321 1,168 0,799 0,909 0,490 0,467 0,061 0,130 0,546 Tempo 1 Tempo 2 Tempo 3 Tempo 4 Tempo 5 Tempo 6 21 [...] 4 Promille 5 Promille 6 0,934 0,025 0,434 0,042 1,684 0,001 1 1 1 1 1 1 19 19 19 19 19 19 0,346 0,876 0,518 0,839 0,210 0,976 Lautstärke 1 Lautstärke 2 Lautstärke 3 Lautstärke 4 Lautstärke 5 Lautstärke …

INHALTSVERZEICHNIS 5 Die Regelsprache und ihre Verarbeitung 35 5.1 Der Weg zur Regelsprache . . . . . . . . . . . . . . . . . . . . 35 5.1.1 Phasenbezeichner und Phasenqualitäten . . . . . . . . 36 5.1.2 Testb [...] Terminale . . . . . . . . . . 44 5.2.4 Die Grammatik als BNF . . . . . . . . . . . . . . . . . 46 5.2.5 Ein Beispiel . . . . . . . . . . . . . . . . . . . . . . . . 47 5.2.6 Die Regeldatei . . . . . . [...] . . . . . . . . . . . . . . . 37 5.1.3 Änderungsanweisungen . . . . . . . . . . . . . . . . . . 38 5.1.4 Regelabgrenzung . . . . . . . . . . . . . . . . . . . . . 38 5.2 Die Regelsprache . . . . . . . …

Figure 5. 5 Urban development change bandwidth of Khon Kaen city in 2037 .................. 118 Figure 5.6 Possible bandwidth of fluvial flood scenarios of Khon Kaen city in the future ... 120 Figure 5.7 High [...] .. 97 5.2 Bandwidth of Possible Futures of Khon Kaen City .............................................. 104 5.2.1 Urban development change bandwidth of Khon Kaen city in the future ..... 104 5.2.2 Climate [...] ........................................ 149 Table 5.5 List of proposed spatial planning-based measures for public health sector ....... 161 Table 5. 6 Matrix analysis for desirable scenario formulation …

EURM10

Sequenzen im relevanten Bereich [−1, 0] - und somit auch die Aussagen der Behauptungen 4.1 bis 4.5 sowie 5.3 und 5.5 - anschaulich dargestellt. Darüber, wie man anhand der zuletzt vorgestellten Erkenntnisse [...] dann für h1 − h2 jeweils: Für k = 5 und i = 2: − 16(−λ3+7λ2−9λ−1) (3λ−5)4 (171(1− λ)9 + 1962λ(1− λ)8 + 10519λ2(1− λ)7 + 32194λ3(1− λ)6 + 60433λ4(1− λ)5 + 71262λ5(1− λ)4 + 52221λ6(1− λ)3 + 22710λ7(1− [...] Beweis zu Behauptung 5.6 zu sehen war, schneiden sich die Se- quenzen s(0) und s(1), egal welche Werte k und λ annehmen, immer an der Stelle x0|1 = − √ v+1 v−1+ √ v+1 . Wegen Behauptung 5.5 ist auch klar, dass …

P:\TEX\SIOPT\19-4\70427\70427.dvi

000 L2: n = 1,000 −5.9232/ − 5.9326 0.0113 5.00 E-SA, N = 2,000 L2 −5.8796/ − 5.8864 0.0575 6.60 E-SA, N = 10,000 L2 −5.9059/ − 5.9058 0.0381 39.80 E-SA, N = 20,000 L2 −5.9151/ − 5.9158 0.0281 74.50 N-SA [...] 2,000 L4: n = 5,000 −5.5855/ − 5.5867 0.0199 25.00 E-SA, N = 2,000 L4 −5.5467/ − 5.5469 0.0597 44.60 E-SA, N = 10,000 L4 −5.5810/ − 5.5812 0.0254 165.10 E-SA, N = 20,000 L4 −5.5901/ − 5.5902 0.0164 382 [...] 0.69 0.0122 4.3 e−4 0.81 1,000 0.00228 3.7 e−5 5.8 0.00257 2.2 e−5 7.3 0.00271 4.5 e−5 8.5 2,000 0.00145 2.1 e−5 11.6 0.00166 1.0 e−5 13.8 0.00179 2.7 e−5 16.4 E-SA ε ( z̃N 1 ) CPU ε ( z̃N 1 ) CPU ε ( …